String formats

String strVal = "a(1), a1(2), a.3(3), a'4 (4), a.5:(5)";
Regex.Replace(strVal, @"[\w\s';.&,:]+\((\d+)\)", "$1") = 1,2,3,4,5
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string dNum = "32.123456";
string.Format("{0:c}", double.Parse(dNum)) = $32.12
string.Format("{0:n}", double.Parse(dNum)) = 32.12
string.Format("{0:D}", DateTime.Now) = Thursday, June 28, 2012
string.Format("{0:T}", DateTime.Now) = 10:59:28 AM
DateTime.Now.ToString("dd/MM/yyyy hh:mm:ss") = 28/06/2012 10:59:28
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decimal dNum = decimal.Parse("32.12345");
Response.Write(dNum.ToString("0.00"));